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-9x^2+115x-300=0
a = -9; b = 115; c = -300;
Δ = b2-4ac
Δ = 1152-4·(-9)·(-300)
Δ = 2425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2425}=\sqrt{25*97}=\sqrt{25}*\sqrt{97}=5\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(115)-5\sqrt{97}}{2*-9}=\frac{-115-5\sqrt{97}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(115)+5\sqrt{97}}{2*-9}=\frac{-115+5\sqrt{97}}{-18} $
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